t^2+2t+48=0

Solution for t^2+2t+48=0 equation:

Simplifying
t2 + 2t + 48 = 0

Reorder the terms:
48 + 2t + t2 = 0

Solving
48 + 2t + t2 = 0

Solving for variable 't'.

Begin completing the square.

Move the constant term to the right:

Add '-48' to each side of the equation.
48 + 2t + -48 + t2 = 0 + -48

Reorder the terms:
48 + -48 + 2t + t2 = 0 + -48

Combine like terms: 48 + -48 = 0
0 + 2t + t2 = 0 + -48
2t + t2 = 0 + -48

Combine like terms: 0 + -48 = -48
2t + t2 = -48

The t term is 2t.  Take half its coefficient (1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
2t + 1 + t2 = -48 + 1

Reorder the terms:
1 + 2t + t2 = -48 + 1

Combine like terms: -48 + 1 = -47
1 + 2t + t2 = -47

Factor a perfect square on the left side:
(t + 1)(t + 1) = -47

Can't calculate square root of the right side.

The solution to this equation could not be determined.